bonsoir de l'aide svp -Développer A= (2x-5)²-(12x-3)(5+x) B=(4x+1)²+2(-3x+6) C= 4x²-16x-(2x+4)(2x-4) Factoriser : D= 100-(4x-5)² E=4x²+20x+25+(-3x+11)(2x+5) F=1

Réponse :

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Explications étape par étape

développer

A=(2x-5)²-(12x-3)(5+x)=

4x²-20x+25-60x-12x²+15+3x=

-8x²-77x+40

B=(4x+1)²+2(-3x+6)=

16x²+8x+1-6x+12=

16x²+2x+13

C=4x²-16x-(2x+4)(2x-4)=

4x²-16x-4x²+8x-8x+16=

-16x+16

factoriser

D= =100-(4x-5)²=

10²-(4x-5)²=

(4x-5+10)(4x-5-10)=

(4x+5)(4x-15)

E=4x²+20x+25+(-3x+11)(2x+5)=

(2x+5)(2x+5)+(-3x+11)(2x+5)=

(2x+5)(2x+5+(-3x+11)=

(2x+5)(2x+5-3x+11)=

(2x+5)(-x+16)

F=16x²-36-(2x-6)(4x+6)=

(4x+6)(4x-6-2x+6)=

2x(4x+6)

G=(5x+3)(7x-1)+(3x-10)(-7x+1)=

(-5x-3)(-7x+1)+(3x-10)(-7x+1)=

(-7x+1)(-5x-3+3x-10)=

(-7x+1)(-2x-13)